(3x+4)(x^2+2x-8)=0

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Solution for (3x+4)(x^2+2x-8)=0 equation: 


Simplifying
(3x + 4)(x2 + 2x + -8) = 0

Reorder the terms:
(4 + 3x)(x2 + 2x + -8) = 0

Reorder the terms:
(4 + 3x)(-8 + 2x + x2) = 0

Multiply (4 + 3x) * (-8 + 2x + x2)
(4(-8 + 2x + x2) + 3x * (-8 + 2x + x2)) = 0
((-8 * 4 + 2x * 4 + x2 * 4) + 3x * (-8 + 2x + x2)) = 0
((-32 + 8x + 4x2) + 3x * (-8 + 2x + x2)) = 0
(-32 + 8x + 4x2 + (-8 * 3x + 2x * 3x + x2 * 3x)) = 0
(-32 + 8x + 4x2 + (-24x + 6x2 + 3x3)) = 0

Reorder the terms:
(-32 + 8x + -24x + 4x2 + 6x2 + 3x3) = 0

Combine like terms: 8x + -24x = -16x
(-32 + -16x + 4x2 + 6x2 + 3x3) = 0

Combine like terms: 4x2 + 6x2 = 10x2
(-32 + -16x + 10x2 + 3x3) = 0

Solving
-32 + -16x + 10x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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